The slant height of a cone is 10 cm and its base radius is 8 cm find total surface area of the cone.

-Added by Prince RawatMathematics » SURFACE AREAS AND VOLUMES

Answer:

Himanshi Verma

Slant height of cone is : 10

Radius of the base is : 8 cm

Total surface area of cone is : πr(l+r)

227×8(10+8)

227×144

= 452.57

-Answered by Himanshi Verma On 19 January 2019:10:07:52 AM(769Average Rating Based on rating)

Answer:

Akki chauhan

slant height of cone is : 10

Radius of the base is : 8 cm

Total surface area of cone is : πr(l+r)

227 ×8(10+8)

227 ×144

= 452.57

-Answered by Akki chauhan On 19 January 2019:10:20:19 AM(770Average Rating Based on rating)

Answer:

khushi chauhan

slant height of cone is : 10

Radius of the base is : 8 cm

Total surface area of cone is : πr(l+r)

227 ×8(10+8)

227 ×144

= 452.57

-Answered by khushi chauhan On 19 January 2019:04:19:50 PM(779Average Rating Based on rating)

Answer:

Himanshi Verma

slant height of cone is : 10

Radius of the base is : 8 cm

Total surface area of cone is : πr(l+r)

227 ×8(10+8)

227 ×144

= 452.57

-Answered by Himanshi Verma On 19 January 2019:04:20:40 PM(781Average Rating Based on rating)

Answer:

praful kumar

slant height of cone is : 10

Radius of the base is : 8 cm

Total surface area of cone is : πr(l+r)

227 ×8(10+8)

227 ×144

= 452.57

-Answered by praful kumar On 20 January 2019:10:01:26 AM(856Average Rating Based on rating)

Answer:

Himanshi Verma

slant height of cone is : 10

Radius of the base is : 8 cm

Total surface area of cone is : πr(l+r)

227 ×8(10+8)

227 ×144

= 452.57

-Answered by Himanshi Verma On 20 January 2019:04:27:57 PM(911Average Rating Based on rating)

Answer:

Master Purushottam

slant height of cone is : 10

Radius of the base is : 8 cm

Total surface area of cone is : πr(l+r)

227 ×8(10+8)

227 ×144

= 452.57

-Answered by Master Purushottam On 24 August 2019:12:15:34 AM(4876Average Rating Based on rating)

You can see here all the solutions of this question by various user for NCERT Solutions. We hope this try will help you in your study and performance.

This Solution may be usefull for your practice and CBSE Exams or All label exams of secondory examination. These solutions or answers are user based solution which may be or not may be by expert but you have to use this at your own understanding of your syllabus.

* Now You can earn points on every asked question and Answer by you. This points make you a valuable user on this forum. This facility is only available for registered user and educators.